$\set{a} \cup \set{b} = \set{a, b}$
Let $a$, $b$ and $c$ denote objects.
From the associativity of pair unions (seePair Unions), we have
\[
(\set{a} \cup \set{b}) \cup \set{b} = \set{a} \cup (\set{b}
\cup \set{c}).
\]
Such sets are so commonplace that we denote the unordered triple of $a$, $b$ and $c$ by $\set{a, b, c}$.
Let $d$ denote an object.
Again, the associativity of pair unions allows
us to drop the parentheses from
\[
(((\set{a} \cup \set{b}) \cup \set{c}) \cup \set{d})).
\]
We denote the unordered quadruple of the objected denoted by $a$, $b$, $c$ and $d$, denote this set by $\set{a, b, c, d}$.
In a similar way we speak of
unordered pentuples,
unordered sextuples,
unordered septuples and so
on.
If we have several objects named, we denote
the set containing these objects be writing
their names in between the left brace $\{$ and
right brace$\}$, separating the names by commas.
For example, if we $A$, $b$, $x$ and $Y$ and
$z$ denote objects, then we denote the set
containing these elements by
\[
\set{A, b, x, Y, z}.
\]