If we interpret a list of two numbers as displacement in a plane, and a list of three numbers as displacement in a space, what of a list of $n$ numbers as displacement in $\R ^n$?
A real vector (or vector, $n$-dimensional vector, $n$-vector) is a length-$n$ list of real numbers.
For $x, y \in \R ^n$, we define the
real vector sum (or
sum) of $x$ and $y$ as
the vector $z \in \R ^n$ where $z_i = x_i +
y_i$ for $i = 1, \dots , n$.
As usual, we denote the sum by $x+y$, so
\[
x + y = (x_1 +y_1, \dots , x_n + y_n).
\] \[
\alpha x = (\alpha x_1, \dots , \alpha x_n).
\]
Our intuition for both of these operations comes from their special cases in $\R ^2$ and $\R ^3$. As usual, the real-vector difference (or difference) of $x$ and $y$ is the vector $z \in \R ^{n}$ defined by $z_i = x_i - y_i$ for $i = 1, \dots , n$. As usual, we denote it by $x - y$, and note that $x - y = x + (-y)$.
The algebra given here for vectors is natural in view of their generalization as $n$-dimensional displacements. However, we keep in mind that this algebra is over lists of numbers, and that these sums and products can be defined on these lists of numbers regardless of interpretation.