We want to record natural numbers. Recall that we denote $\varnothing$ by 0, the successor of 0 by 1 and the sucessor of 1 by 2. 1 is the success of 0 and 2 is the successor of 1. We agree to continue 3, 4, 5, 6, 7, 9, each the successor if its predecessor in the list. Given these numbers, how should we denote the successor to 9?
We could of course have a new symbol, and denote the successor of 9 by this symbol. But then we would need as many symbols are there are natural numbers. And the natural numbers are infinite (not finite!). The following is a trick around this, re-using our ten symbols. Why ten?... How many fingers do you have?
The natural notation (or
base-ten notation,
base-10 notation) for a
natural number is a list of elements of the
set
\[
\set{0, 1, 2, 3, 4, 5, 6, 7, 8, 9}
\] \[
\eta _1 + \eta _2\cdot \ssuc{9} + \eta _3\cdot (\ssuc{9})^2 +
\cdots + \eta _k\cdot (\ssuc{9})^{k-1}
\] \[
\sum_{i = 1}^{k} \eta _i\cdot (\ssuc{9})^{i-1}
\]
In a slightly different but universally standard
way, we denote the natural notation $\eta =
(\eta _1, \dots , \eta _k)$ by
\[
\eta _k\eta _{k-1} \cdots \eta _2\eta _1
\]
Some examples will help, and illustrate the
notation.
Here is a natural notation for some number:
$(0, 1)$.
Which number?
Well, we have agreed that it is the number
\[
0 + 1\cdot \ssuc{9} = \ssuc{9}
\]
Here is a natural notation for some number:
$(3, 2, 1)$.
Which number?
Well, we have agreed that it is the number
\[
1 + 2\cdot \ssuc{9} + 3\cdot (\ssuc{9})^2
\] \[
1 + 2\cdot 10 + 3\cdot (10)^2
\]
We see that powers of $10$ show up in the sum for the number corresponding to this notation. We name these powers. 100 is the number hundred. 1000 is the number thousand