We want finite measures.1
A measurable set is measure-finite (or when clear that we do not mean finite in the sense of Finite sets), a set is finite) if its measure is a real number (as opposed to the only alternative, $+\infty$). The measure space itself is measure-finite if the base set is finite.
A measurable set is sigma-finite if there exists a sequence of finite measurable sets whose union is the set.2 The measure space itself is sigma-finite if the base set is sigma finite.
Let $(A, \mathcal{A} , \mu )$ be a measure space. It is finite if $\mu (A) < +\infty$.
The counting measure on $(A, \mathcal{A} )$ is finite if and only if the base set is finite. It is sigma finite if and only if the base set is a union of a sequence of finite sets.
If $\mathcal{A} = 2^A$, then the counting measure is sigma finite if and only if $A$ is countable.